# Leetcode: Backspace String Compare

Backspace String Compare

Similar Problems:

Given two strings S and T, return if they are equal when both are typed into empty text editors. # means a backspace character.

Example 1:

```Input: S = "ab#c", T = "ad#c"
Output: true
Explanation: Both S and T become "ac".
```

Example 2:

```Input: S = "ab##", T = "c#d#"
Output: true
Explanation: Both S and T become "".
```

Example 3:

```Input: S = "a##c", T = "#a#c"
Output: true
Explanation: Both S and T become "c".
```

Example 4:

```Input: S = "a#c", T = "b"
Output: false
Explanation: S becomes "c" while T becomes "b".
```

Note:

1. 1 <= S.length <= 200
2. 1 <= T.length <= 200
3. S and T only contain lowercase letters and ‘#’ characters.

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

• Solution: Time O(n), Space O(n)
```// Blog link: https://code.dennyzhang.com/backspace-string-compare
// Basic Ideas:
// Complexity: Time O(n), Space O(n)
func getString(S string) string {
ret := []string{}
for _, ch := range S {
if ch != '#' {
ret = append(ret, string(ch))
} else {
if len(ret) != 0 { ret = ret[0:len(ret)-1] }
}
}
return strings.Join(ret, "")
}

func backspaceCompare(S string, T string) bool {
return getString(S) == getString(T)
}
```

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