# Leetcode: Binary Tree Inorder Traversal

Binary Tree Inorder Traversal

Similar Problems:

Given a binary tree, return the inorder traversal of its nodes’ values.

For example:

```Given binary tree [1,null,2,3],
1
\
2
/
3
return [1,3,2].
```

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

```## Blog link: https://code.dennyzhang.com/binary-tree-inorder-traversal
# Definition for a binary tree node.
# class TreeNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None

class Solution(object):
def inorderTraversal(self, root):
"""
:type root: TreeNode
:rtype: List[int]
"""
if root is None:
return []
res = []
stack = []
p = root
# initialize the stack
while p:
stack.append(p)
p = p.left

# DFS
while(len(stack) != 0):
top_item = stack.pop()
res.append(top_item.val)
if top_item.right:
p = top_item.right
while p:
stack.append(p)
p = p.left
return res
```

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