Leetcode: Department Highest Salary

Department Highest Salary



Similar Problems:


The Employee table holds all employees. Every employee has an Id, a salary, and there is also a column for the department Id.

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
+----+-------+--------+--------------+

The Department table holds all departments of the company.

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

Write a SQL query to find employees who have the highest salary in each of the departments. For the above tables, Max has the highest salary in the IT department and Henry has the highest salary in the Sales department.

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| Sales      | Henry    | 80000  |
+------------+----------+--------+

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.


## Blog link: https://code.dennyzhang.com/department-highest-salary
select Department.Name as Department, t3.Name as Employee, t3.Salary
from Employee as t3 inner join
     (select t1.Salary, t1.DepartmentId, count(1) as rank
        from (select distinct Salary, DepartmentId from Employee) as t1
             inner join
             (select distinct Salary, DepartmentId from Employee) as t2
             on t1.DepartmentId = t2.DepartmentId
        where t1.Salary <= t2.Salary
        group by t1.Salary, t1.DepartmentId) as t4
      inner join Department
      on t3.DepartmentId = t4.DepartmentId and t3.Salary = t4.Salary 
      and t3.DepartmentId = Department.Id
where t4.rank<4
order by t3.DepartmentId asc, t3.Salary desc;
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