LeetCode: Department Top Three Salaries

Department Top Three Salaries

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• CheatSheet: SQL & MySql
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• Tag: #sql

The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id.

+----+-------+--------+--------------+
| Id | Name  | Salary | DepartmentId |
+----+-------+--------+--------------+
| 1  | Joe   | 70000  | 1            |
| 2  | Henry | 80000  | 2            |
| 3  | Sam   | 60000  | 2            |
| 4  | Max   | 90000  | 1            |
| 5  | Janet | 69000  | 1            |
| 6  | Randy | 85000  | 1            |
+----+-------+--------+--------------+

The Department table holds all departments of the company.

+----+----------+
| Id | Name     |
+----+----------+
| 1  | IT       |
| 2  | Sales    |
+----+----------+

Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows.

+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT         | Max      | 90000  |
| IT         | Randy    | 85000  |
| IT         | Joe      | 70000  |
| Sales      | Henry    | 80000  |
| Sales      | Sam      | 60000  |
+------------+----------+--------+

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

## https://code.dennyzhang.com/department-top-three-salaries
select t4.Name as Department, t3.Name as Employee, t3.Salary
from
    (select t1.Id, t1.Name, t1.Salary, t1.DepartmentId, count(1) as rank
    from Employee as t1 inner join Employee as t2
    on t1.DepartmentId = t2.DepartmentId
    where t1.Salary <= t2.Salary
    group by t1.Id, t1.Name, t1.Salary, t1.DepartmentId) as t3
    inner join Department as t4
    on t3.DepartmentId = t4.Id
where rank<=3
order by t4.Name, t3.Salary desc