LeetCode: Department Top Three Salaries Posted on February 12, 2018July 26, 2020 by braindenny Department Top Three Salaries Similar Problems: CheatSheet: SQL & MySql CheatSheet: Leetcode For Code Interview CheatSheet: Common Code Problems & Follow-ups Tag: #sql The Employee table holds all employees. Every employee has an Id, and there is also a column for the department Id. +----+-------+--------+--------------+ | Id | Name | Salary | DepartmentId | +----+-------+--------+--------------+ | 1 | Joe | 70000 | 1 | | 2 | Henry | 80000 | 2 | | 3 | Sam | 60000 | 2 | | 4 | Max | 90000 | 1 | | 5 | Janet | 69000 | 1 | | 6 | Randy | 85000 | 1 | +----+-------+--------+--------------+ The Department table holds all departments of the company. +----+----------+ | Id | Name | +----+----------+ | 1 | IT | | 2 | Sales | +----+----------+ Write a SQL query to find employees who earn the top three salaries in each of the department. For the above tables, your SQL query should return the following rows. +------------+----------+--------+ | Department | Employee | Salary | +------------+----------+--------+ | IT | Max | 90000 | | IT | Randy | 85000 | | IT | Joe | 70000 | | Sales | Henry | 80000 | | Sales | Sam | 60000 | +------------+----------+--------+ Github: code.dennyzhang.com Credits To: leetcode.com Leave me comments, if you have better ways to solve. ## https://code.dennyzhang.com/department-top-three-salaries select t4.Name as Department, t3.Name as Employee, t3.Salary from (select t1.Id, t1.Name, t1.Salary, t1.DepartmentId, count(1) as rank from Employee as t1 inner join Employee as t2 on t1.DepartmentId = t2.DepartmentId where t1.Salary <= t2.Salary group by t1.Id, t1.Name, t1.Salary, t1.DepartmentId) as t3 inner join Department as t4 on t3.DepartmentId = t4.Id where rank<=3 order by t4.Name, t3.Salary desc Post Views: 5