Find Anagram Mappings

Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.

We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.

These lists A and B may contain duplicates. If there are multiple answers, output any of them.

For example, given A = [12, 28, 46, 32, 50] B = [50, 12, 32, 46, 28] We should return [1, 4, 3, 2, 0] as P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on.

Note:

- A, B have equal lengths in range [1, 100].
- A[i], B[i] are integers in range [0, 10^5].

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

#!/usr/bin/env python ## Blog link: https://code.dennyzhang.com/find-anagram-mappings ## Basic Ideas: ## Complexity: Time O(n*n), Space O(1) ## Assumption: whether I can change B? class Solution(object): def anagramMappings(self, A, B): """ :type A: List[int] :type B: List[int] :rtype: List[int] """ length = len(A) selected_list = [0] * length result = [] for item in A: # print("item: %d" % (item)) for i in xrange(length): if item == B[i]: result.append(i) B[i] = None break return result # s = Solution() # print s.anagramMappings([21,5,74,5,74,21], [21,5,74,74,5,21])

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