LeetCode: Find Anagram Mappings

Find Anagram Mappings

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• Tag: #anagram

Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.

We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.

These lists A and B may contain duplicates. If there are multiple answers, output any of them.

For example, given

A = [12, 28, 46, 32, 50]
B = [50, 12, 32, 46, 28]
We should return
[1, 4, 3, 2, 0]
as P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on.

Note:

1. A, B have equal lengths in range [1, 100].
2. A[i], B[i] are integers in range [0, 10^5].

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

#!/usr/bin/env python
## https://code.dennyzhang.com/find-anagram-mappings
## Basic Ideas: 
## Complexity: Time O(n^2), Space O(1)
## Assumption: whether I can change B?
class Solution(object):
    def anagramMappings(self, A, B):
        """
        :type A: List[int]
        :type B: List[int]
        :rtype: List[int]
        """
        length = len(A)
        selected_list = [0] * length
        result = []
        for item in A:
            # print("item: %d" % (item))
            for i in xrange(length):
                if item == B[i]:
                    result.append(i)
                    B[i] = None
                    break
        return result

# s = Solution()
# print s.anagramMappings([21,5,74,5,74,21], [21,5,74,74,5,21])