Leetcode: Flip Game

Flip Game



Similar Problems:


You are playing the following Flip Game with your friend: Given a string that contains only these two characters: + and -, you and your friend take turns to flip two consecutive “++” into “–“. The game ends when a person can no longer make a move and therefore the other person will be the winner.

Write a function to compute all possible states of the string after one valid move.

For example, given s = “++“, after one move, it may become one of the following states:

[
  "--++",
  "+--+",
  "++--"
]

If there is no valid move, return an empty list [].

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.


## Blog link: https://code.dennyzhang.com/flip-game
## Basic Ideas: One pass
## Complexity: Time O(n), Space O(1)
class Solution:
    def generatePossibleNextMoves(self, s):
        """
        :type s: str
        :rtype: List[str]
        """
        res = []
        for i in range(1, len(s)):
            if s[i-1:i+1] == '++':
                res.append(s[:i-1] + '--' + s[i+1:])
        return res
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