Skip to content

Prepare For Coder Interview – Denny

  • Basic
  • Medium
  • Hard
  • Architect
  • Life

Leetcode: Heaters

Posted on January 27, 2018September 23, 2019 by braindenny

Heaters



Similar Problems:

  • Shortest Word Distance
  • CheatSheet: Leetcode For Code Interview
  • Tag: #inspiring, #classic

Winter is coming! Your first job during the contest is to design a standard heater with fixed warm radius to warm all the houses.

Now, you are given positions of houses and heaters on a horizontal line, find out minimum radius of heaters so that all houses could be covered by those heaters.

So, your input will be the positions of houses and heaters seperately, and your expected output will be the minimum radius standard of heaters.

Note:

  1. Numbers of houses and heaters you are given are non-negative and will not exceed 25000.
  2. Positions of houses and heaters you are given are non-negative and will not exceed 10^9.
  3. As long as a house is in the heaters’ warm radius range, it can be warmed.
  4. All the heaters follow your radius standard and the warm radius will the same.

Example 1:

Input: [1,2,3],[2]
Output: 1
Explanation: The only heater was placed in the position 2, and if we use the radius 1 standard, then all the houses can be warmed.

Example 2:

Input: [1,2,3,4],[1,4]
Output: 1
Explanation: The two heater was placed in the position 1 and 4. We need to use radius 1 standard, then all the houses can be warmed.

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.


// https://code.dennyzhang.com/heaters
// Basic Ideas: One pass
// For each house, find the nearest heater
// Complexity: Time O(n*log(n)), Space O(1)
import "sort"
func abs(v int) int {
    if v<0 { return -v }
    return v
}

func findRadius(houses []int, heaters []int) int {
    sort.Ints(houses)
    sort.Ints(heaters)
    res := 0
    i := 0
    for _, house := range houses {
        // find the nearest heater
        for i<len(heaters)-1 && abs(heaters[i]-house) >= abs(heaters[i+1]-house) {
            i++
        }
        if abs(heaters[i]-house) > res { res = abs(heaters[i]-house) }
    }
    return res
}
linkedin
github
slack

Post Views: 5
Posted in AmusingTagged #classic, #inspiring

Post navigation

Leetcode: Range Addition II
Leetcode: Elimination Game

Leave a Reply Cancel reply

Your email address will not be published.

Tags

#array #backtracking #bfs #binarytree #bitmanipulation #classic #codetemplate #combination #dfs #dynamicprogramming #game #graph #greedy #heap #inspiring #interval #linkedlist #manydetails #math #misc #palindrome #recursive #slidingwindow #stack #string #subarray #trie #twopointer #twosum baseconversion binarysearch concurrency editdistance hashmap knapsack monotone oodesign presum redo review rotatelist series sql treetraversal unionfind

Recent Posts

  • Leetcode: Palindrome Partitioning III
  • Leetcode: Biggest Single Number
  • Leetcode: Max Consecutive Ones II
  • Leetcode: Minimum Cost to Connect Sticks
  • Leetcode: Minimum Swaps to Group All 1’s Together

Recent Comments

    Archives

    Categories

    • Amusing
    • Basic
    • Easy
    • Hard
    • Life
    • Medium
    • Resource
    • Review
    • Series
    • Uncategorized
    Proudly powered by WordPress | Theme: petals by Aurorum.