K Closest Points to Origin

Similar Problems:

We have a list of points on the plane. Find the K closest points to the origin (0, 0).

(Here, the distance between two points on a plane is the Euclidean distance.)

You may return the answer in any order. The answer is guaranteed to be unique (except for the order that it is in.)

Example 1:

Input: points = [[1,3],[-2,2]], K = 1 Output: [[-2,2]] Explanation: The distance between (1, 3) and the origin is sqrt(10). The distance between (-2, 2) and the origin is sqrt(8). Since sqrt(8) < sqrt(10), (-2, 2) is closer to the origin. We only want the closest K = 1 points from the origin, so the answer is just [[-2,2]].

Example 2:

Input: points = [[3,3],[5,-1],[-2,4]], K = 2 Output: [[3,3],[-2,4]] (The answer [[-2,4],[3,3]] would also be accepted.)

Note:

- 1 <= K <= points.length <= 10000
- -10000 < points[i][0] < 10000
- -10000 < points[i][1] < 10000

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

// Blog link: https://code.dennyzhang.com/k-closest-points-to-origin // Basic Idea: sort // Complexity: Time O(n*log(n)), Space O(n) import "sort" type Point struct { i int v int } func kClosest(points [][]int, K int) [][]int { l := []Point{} for i, p := range points { l = append(l, Point{i, p[0]*p[0]+p[1]*p[1]}) } sort.Slice(l, func(i, j int) bool { return l[i].v < l[j].v }) res := [][]int{} for i := K-1; i>=0; i-- { res = append(res, points[l[i].i]) } return res }