Linked List Components

Similar Problems:

We are given head, the head node of a linked list containing unique integer values.

We are also given the list G, a subset of the values in the linked list.

Return the number of connected components in G, where two values are connected if they appear consecutively in the linked list.

Example 1:

Input: head: 0->1->2->3 G = [0, 1, 3] Output: 2 Explanation: 0 and 1 are connected, so [0, 1] and [3] are the two connected components.

Example 2:

Input: head: 0->1->2->3->4 G = [0, 3, 1, 4] Output: 2 Explanation: 0 and 1 are connected, 3 and 4 are connected, so [0, 1] and [3, 4] are the two connected components.

Note:

- If N is the length of the linked list given by head, 1 <= N <= 10000.
- The value of each node in the linked list will be in the range [0, N – 1].
- 1 <= G.length <= 10000.
- G is a subset of all values in the linked list.

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

## Blog link: https://code.dennyzhang.com/linked-list-components # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def numComponents(self, head, G): """ :type head: ListNode :type G: List[int] :rtype: int """ ## Basic Ideas: One pass for linked list ## set ## Complexity: Time O(n), Space O(n) nodes_set = set(G) res = 0 node = head new_start = True while node: if node.val in nodes_set: if new_start: res += 1 new_start = False else: new_start = True node = node.next return res

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