# Leetcode: Median Employee Salary

Median Employee Salary

Similar Problems:

The Employee table holds all employees. The employee table has three columns: Employee Id, Company Name, and Salary.

```+-----+------------+--------+
|Id   | Company    | Salary |
+-----+------------+--------+
|1    | A          | 2341   |
|2    | A          | 341    |
|3    | A          | 15     |
|4    | A          | 15314  |
|5    | A          | 451    |
|6    | A          | 513    |
|7    | B          | 15     |
|8    | B          | 13     |
|9    | B          | 1154   |
|10   | B          | 1345   |
|11   | B          | 1221   |
|12   | B          | 234    |
|13   | C          | 2345   |
|14   | C          | 2645   |
|15   | C          | 2645   |
|16   | C          | 2652   |
|17   | C          | 65     |
+-----+------------+--------+
```

Write a SQL query to find the median salary of each company. Bonus points if you can solve it without using any built-in SQL functions.

```+-----+------------+--------+
|Id   | Company    | Salary |
+-----+------------+--------+
|5    | A          | 451    |
|6    | A          | 513    |
|12   | B          | 234    |
|9    | B          | 1154   |
|14   | C          | 2645   |
+-----+------------+--------+
```

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

```## Blog link: https://code.dennyzhang.com/median-employee-salary
select t1.Id as Id, t1.Company, t1.Salary
from Employee as t1 inner join Employee as t2
on t1.Company = t2.Company
group by t1.Id
having abs(sum(CASE when t2.Salary<t1.Salary then 1
when t2.Salary>t1.Salary then -1
when t2.Salary=t1.Salary and t2.Id<t1.Id then 1
when t2.Salary=t1.Salary and t2.Id>t1.Id then -1
else 0 end)) <= 1
order by t1.Company, t1.Salary, t1.Id
```

Share It, If You Like It.