Leetcode: Monthly Transactions II – Prepare For Coder Interview

Monthly Transactions II

Similar Problems:

Table: Transactions

+----------------+---------+
| Column Name    | Type    |
+----------------+---------+
| id             | int     |
| country        | varchar |
| state          | enum    |
| amount         | int     |
| trans_date     | date    |
+----------------+---------+
id is the primary key of this table.
The table has information about incoming transactions.
The state column is an enum of type ["approved", "declined"].

Table: Chargebacks

+----------------+---------+
| Column Name    | Type    |
+----------------+---------+
| trans_id       | int     |
| charge_date    | date    |
+----------------+---------+
Chargebacks contains basic information regarding incoming chargebacks from some transactions placed in Transactions table.
trans_id is a foreign key to the id column of Transactions table.
Each chargeback corresponds to a transaction made previously even if they were not approved.

Write an SQL query to find for each month and country, the number of approved transactions and their total amount, the number of chargebacks and their total amount.

Note: In your query, given the month and country, ignore rows with all zeros.

The query result format is in the following example:

Transactions table:

+------+---------+----------+--------+------------+
| id   | country | state    | amount | trans_date |
+------+---------+----------+--------+------------+
| 101  | US      | approved | 1000   | 2019-05-18 |
| 102  | US      | declined | 2000   | 2019-05-19 |
| 103  | US      | approved | 3000   | 2019-06-10 |
| 104  | US      | approved | 4000   | 2019-06-13 |
| 105  | US      | approved | 5000   | 2019-06-15 |
+------+---------+----------+--------+------------+

Chargebacks table:
+------------+------------+
| trans_id   | trans_date |
+------------+------------+
| 102        | 2019-05-29 |
| 101        | 2019-06-30 |
| 105        | 2019-09-18 |
+------------+------------+

Result table:
+----------+---------+----------------+-----------------+-------------------+--------------------+
| month    | country | approved_count | approved_amount | chargeback_count  | chargeback_amount  |
+----------+---------+----------------+-----------------+-------------------+--------------------+
| 2019-05  | US      | 1              | 1000            | 1                 | 2000               |
| 2019-06  | US      | 3              | 12000           | 1                 | 1000               |
| 2019-09  | US      | 0              | 0               | 1                 | 5000               |
+----------+---------+----------------+-----------------+-------------------+--------------------+

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

Solution: union all

## https://code.dennyzhang.com/monthly-transactions-ii
select month, country,
    sum(case when type='approved' then 1 else 0 end) as approved_count,
    sum(case when type='approved' then amount else 0 end) as approved_amount,
    sum(case when type='chargeback' then 1 else 0 end) as chargeback_count,
    sum(case when type='chargeback' then amount else 0 end) as chargeback_amount
from (
    (
    select left(t.trans_date, 7) as month, t.country, amount,'approved' as type
    from Transactions as t
    where state='approved'
    ) 
    union all (
    select left(c.trans_date, 7) as month, t.country, amount,'chargeback' as type
    from Transactions as t join Chargebacks as c
    on t.id = c.trans_id
    )
) as tt
group by tt.month, tt.country

Solution: use union to compensate the missing support of full outer join

## https://code.dennyzhang.com/monthly-transactions-ii
select month, country,
    sum(case when type='approved' then count else 0 end) as approved_count,
    sum(case when type='approved' then amount else 0 end) as approved_amount,
    sum(case when type='chargeback' then count else 0 end) as chargeback_count,
    sum(case when type='chargeback' then amount else 0 end) as chargeback_amount
from (
    (
    select left(t.trans_date, 7) as month, t.country,
    count(1) as count, sum(amount) as amount,'approved' as type
    from Transactions as t left join Chargebacks as c
    on t.id = c.trans_id
    where state='approved'
    group by left(t.trans_date, 7), t.country
    ) 
    union (
    select left(c.trans_date, 7) as month, t.country,
        count(1) as count, sum(amount) as amount,'chargeback' as type
    from Transactions as t join Chargebacks as c
    on t.id = c.trans_id
    group by left(c.trans_date, 7), t.country       
    )
) as tt
group by tt.month, tt.country

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