LeetCode: Smallest Range I

Smallest Range I

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• Tag: #interval

Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i].

After this process, we have some array B.

Return the smallest possible difference between the maximum value of B and the minimum value of B.

Example 1:

Input: A = [1], K = 0
Output: 0
Explanation: B = [1]

Example 2:

Input: A = [0,10], K = 2
Output: 6
Explanation: B = [2,8]

Example 3:

Input: A = [1,3,6], K = 3
Output: 0
Explanation: B = [3,3,3] or B = [4,4,4]

Note:

1. 1 <= A.length <= 10000
2. 0 <= A[i] <= 10000
3. 0 <= K <= 10000

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

• Solution:

// https://code.dennyzhang.com/smallest-range-i
// Basic Ideas:
// Find the min and max. 
// Then compare [min, min+k] with [max-k, max]
// Complexity: Time O(n), Space O(1)
func smallestRangeI(A []int, K int) int {
    min, max := A[0], A[0]
    for i:=1; i<len(A); i++ {
        if A[i]>max { max=A[i] }
        if A[i]<min { min=A[i] }
    }
    v:= max-min-2*K
    if v <= 0 { return 0 }
    return v    
}