# Leetcode: Split Array into Fibonacci Sequence

Split Array into Fibonacci Sequence

Similar Problems:

Given a string S of digits, such as S = “123456579”, we can split it into a Fibonacci-like sequence [123, 456, 579].

Formally, a Fibonacci-like sequence is a list F of non-negative integers such that:

0 <= F[i] <= 2^31 – 1, (that is, each integer fits a 32-bit signed integer type);
F.length >= 3;
and F[i] + F[i+1] = F[i+2] for all 0 <= i < F.length – 2.
Also, note that when splitting the string into pieces, each piece must not have extra leading zeroes, except if the piece is the number 0 itself.

Return any Fibonacci-like sequence split from S, or return [] if it cannot be done.

Example 1:

```Input: "123456579"
Output: [123,456,579]
```

Example 2:

```Input: "11235813"
Output: [1,1,2,3,5,8,13]
```

Example 3:

```Input: "112358130"
Output: []
```

Example 4:

```Input: "0123"
Output: []
Explanation: Leading zeroes are not allowed, so "01", "2", "3" is not valid.
```

Example 5:

```Input: "1101111"
Output: [110, 1, 111]
Explanation: The output [11, 0, 11, 11] would also be accepted.
```

Note:

1. 1 <= S.length <= 200
2. S contains only digits.

Github: code.dennyzhang.com

Credits To: leetcode.com

Leave me comments, if you have better ways to solve.

• Solution: Brute Force

General Thinkings:

```The first two elements of the array uniquely determine the rest of the sequence.
```
```// Blog link: https://code.dennyzhang.com/split-array-into-fibonacci-sequence
// Basic Ideas: Brute Force
// num1: S[0:i], num2: S[i:j]
// Complexity: Time ?, Space O(n)
import "strconv"
func splitString(S string, num1 int, num2 int) []int {
if num1>(1<<31 - 1) || num2>(1<<31 - 1) { return []int{} }
res := []int{num1, num2}
for len(S) != 0 {
num3 := num1+num2
if num3>(1<<31 - 1) { return []int{} }
str := strconv.Itoa(num3)
if strings.Index(S, str) != 0 { return []int{} }
S = S[len(str):]
num1, num2 = num2, num3
res = append(res, num3)
}
return res
}

func splitIntoFibonacci(S string) []int {
// num1: S[0:i], num2: S[i:j]
for i:=1; i<len(S)-2; i++ {
for j:=i+1; j<len(S)-1; j++ {
if S[0] == '0' && S[0:i] != "0" { continue }
if S[i] == '0' && S[i:j] != "0" { continue }
num1, _ := strconv.Atoi(S[0:i])
num2, _ := strconv.Atoi(S[i:j])
l := splitString(S[j:], num1, num2)
if len(l) >=3 { return l }
}
}
return []int{}
}
```

Connect with Denny In LinkedIn Or Slack

Share It, If You Like It.